Leonardo da Vinci (1452-1519) made outstanding illustrations for Luca Pacioli's 1509 book "The Divine Proportion", in which they described "elevated" forms of many polyhedra. In the Seoul Bridges meeting this year, Rinus Roelofs presented a beautiful paper on the similarities and differences between Da Vinci's elevations and Kepler's stellations.
For details, check the following pdf file:
Rinus Roelofs,
Elevations and Stellations,
Proceedings of Bridges 2014: Mathematics, Music, Art, Architecture, Culture, 235-242.
Figure 1 and 2 in the paper are original illustrations made by Leonardo da Vinci:
It is interesting that bead models for the five elevated regular polyhedra can be built easily with great effects. Among them, elevated cube and dodecahedron are more flexible as expected.
Also, these five elevated Platonic solids can be viewed as nonconvex deltahedra with the names,
triakis tetrahedron, tetrakis hexahedron,
triakis octahedron
(stella octangula),
pentakis dodecahedron,
and triakis icosahedron, respectively.
Additionally, the elevated icosidodecahedron was also illustrated beautifully by Da Vinci in the book.
The corresponding bead model can also be built!
Showing posts with label Platonic Solids. Show all posts
Showing posts with label Platonic Solids. Show all posts
Tuesday, October 21, 2014
Sunday, December 23, 2012
Oval shaped beads
I bought some plastic oval shaped beads a few months ago. I only made a buckyball with this kind of beads and never used them again. I saw these beads this afternoon accidentally and decided to make some more simple models with these oval shaped beads.
So, here are five Platonic solids and a rhombic triacontahedron I made.
Wednesday, September 12, 2012
Sangaku problem and C20
In the book "算法助述" I got from Mr. Horibe, there is an interesting problem in pp. 51-52 as shown in the following picture. As I mentioned before, Mr. Horibe made two beautiful bead models with a large metal sphere inside. And more importantly, large and small balls have the correct ratio of radii, R/r=sqrt{5}. He told me that he gave one of these two models to Hidetoshi Fukagawa, the author of the book "Sacred Mathematica - Japanese Temple Geometry", because, through Dr. Fukagawa, he knew so much about these interesting Japanese sangaku problems.
This Sangaku problem was originally proposed by Ishikawa Nagamasa and written on a tablet hung in 1798 in Tokyo’s Gyuto Tennosha shrine. I was quite surprised by that I could understand this ancient problem without any translation. It was written in Chinese (or Kanji):
"今有以小球三十個如圖圍大球,小球者各切臨球四個與大球,小球徑三百零五寸,問大球徑幾何?
答曰:大球徑六百八十二寸。"
In English:
Thirty small balls cover one big ball where each small ball touches four other small balls and big balls.
The radius of small ball is 305 inches. Find the radius of large ball.
Answer: The radius of large ball is 682 inches.
In the page 52 of the book, there are some explanations on how to reach the answer by noting that thirty balls are located on the thirty vertices of an icosidodecahedron. It was written with some Japanese characters which I don't understand. But it is not hard to guess the rationale. One can see that if one starts from an arbitrarily chosen small ball, then moves to next ball along a fixed direction, and then the next one along the same direction. Eventually, one would trace over exactly 10 balls which are located on the large circle of a sphere with the radius equal to the sum of radii of small and large balls. Using some trigonometry, one can get the answer.
"今有以小球三十個如圖圍大球,小球者各切臨球四個與大球,小球徑三百零五寸,問大球徑幾何?
答曰:大球徑六百八十二寸。"
In English:
Thirty small balls cover one big ball where each small ball touches four other small balls and big balls.
The radius of small ball is 305 inches. Find the radius of large ball.
Answer: The radius of large ball is 682 inches.
In the page 52 of the book, there are some explanations on how to reach the answer by noting that thirty balls are located on the thirty vertices of an icosidodecahedron. It was written with some Japanese characters which I don't understand. But it is not hard to guess the rationale. One can see that if one starts from an arbitrarily chosen small ball, then moves to next ball along a fixed direction, and then the next one along the same direction. Eventually, one would trace over exactly 10 balls which are located on the large circle of a sphere with the radius equal to the sum of radii of small and large balls. Using some trigonometry, one can get the answer.
Tuesday, May 15, 2012
Bead valence sphere model of tetra-t-butyl tetrahedrane
The tetrahedrane derivative with four tert-butyl substituents, tetra-t-butyl tetrahedrane, was synthesized by the Austrian chemist,Günther Maier, in 1978. Here is the bead valence sphere model of this interesting molecule I made this afternoon. I think the hardest part to make molecules with many sp3 centers how to control the force evenly in the whole weaving process.
Tuesday, April 10, 2012
Bead VSM of tetrahedrane
I should forget another platonic alkane, the tetrahedrane.
The shape of this molecule based on the valence sphere model is just like 10 spheres close packed in a tetrahedron. Which models, valence sphere model or ball-and-stick model, is closer to the true shape of a tetrahedrane molecule?
Bead VSM of dodecahedrane
In principle, we can make the valence sphere model for any molecule with beads. But in practice, it is a little bit hard
to thread the Nylon cord through a bead structure with tetravalent bonds, which are common for most molecules though.
But anyway, I made a bead VSM of dodecahedrane, C20H20.
But anyway, I made a bead VSM of dodecahedrane, C20H20.
Bead VSM of cubane
I just made a bead VSM (valence sphere model) of cubane (C8H8) by myself.
The structure looks neat to me. Every valence electron pair is faithfully represented by a big bead, purple for CC bond and pink for CH bond.
Small beads which have no chemical meaning are used to bind the pink beads to the central carbon cube. I didn't distinguish CC bonds from CH bonds. In principle,
electron pairs responsible for these two types of chemical bonds should have different momenta. So they should have different
sizes of charge clouds.
Monday, June 28, 2010
A dodecahedral ball made with bamboo
Thursday, June 24, 2010
Tuesday, April 6, 2010
Monday, November 16, 2009
Beaded icosahedrons
Beaded models for icosahedron are harder to make. This is because each vertex has five edges connected to it, so one has to face a pentavalent coordination. It is very difficult, if not impossible, to make a pentavalent coordinate with spherical beads. But if want use beads with long aspect ratio, stable and beautiful icosahedral structures can still be made.

Wednesday, November 4, 2009
Saturday, December 27, 2008
Thursday, December 18, 2008
Tetrahedron
Tuesday, July 15, 2008
Platonic solids with cylindrical bonds
Cylindrical beads that have capsule shape are perfect pedagogical materials for creating physical models of fullerenes since they can look like the chemists' intuition of chemical bonds and, at the same time, effectively mimic the steric repulsion among different beads. To demonstrate these points, here, we use these beads to create the five Platonic solids.

Monday, July 14, 2008
Chemical bonds as cylindrical beads
Monday, April 28, 2008
Platonic Solids
Wednesday, December 5, 2007
Subscribe to:
Posts (Atom)